Like do you see any way we can code this a little bit better? If we were to look at our midpoint here, so say actually, no, not that we did the wrong thing. Templates let you quickly answer FAQs or store snippets for re-use. If we reach the end without triggering either condition, we can return true. Well, I use count to remember how many descending pairs in the array, if count>=2, obviously we cannot modify a single element to obtain a non-descreaing array, so we return False.When count equals one, we check if we can modify nums[i] (the first one in the descending pair, by decreasing it) or nums[i+1] (the second one in the descending pair, by increasing it), if in both situations, we . But if you had it, and another good candidate in target, I'll probably prefer you. Can I use the door leading from Vatican museum to St. Peter's Basilica? I'll let you turn your fan back on. Built on Forem the open source software that powers DEV and other inclusive communities. : I hear ya. Example 1: Thank you for your valuable feedback! You've seen the past, right? So let's get to this. And then for this case, this is basically this. Yeah I'm just I'm just gonna do a quick analysis on this. And again, this is kind of a little bit weird, because I know it's going to be binary search but when I look at this, and I look at these statements nothing here tells me that the array is necessarily ordered in any way like I look at it and I think, all right, peak element where it's greater than its neighbours, we can have 010, then we can have negative five, we have four, negative six, and then we can go back to do with like, 7, 8, 7. So current element is now three come through or previous elements is now three current elements is now two previous elements is greater than current element. OverflowAI: Where Community & AI Come Together, Behind the scenes with the folks building OverflowAI (Ep. Okay so, O(N), O log(n) time this here would be like, I mean, obviously, I know, this is a binary search problem, but even if I didn't know, there'd be a giant int right there. LeetCode Solutions: https://www.youtube.com/playlist?list=PL1w8k37X_6L86f3PUUVFoGYXvZiZHde1SMay Leetcoding Challenge 2021: https://www.youtube.com/playlist?l. Once suspended, seanpgallivan will not be able to comment or publish posts until their suspension is removed. But let's say that P one and maybe another P two, somewhere here, and you put it elsewhere, this will allow you to navigate this visually, it's, it's easier to see for the interview, it could be the actual p one or P two, whatever it is. So even if you've seen the question before, that's totally fine. Okay, so we're gonna get like a, you know, take a step back at this. And so, we given that we know that the in assuming that Okay, so let me just delete this. May 2021 Leetcode ChallengeLeetcode - Non-decreasing Array #665Difficulty: Medium I'll just paste it in leetcode here, and so you can check it out later, I had a different question prepared. To answer that, we'll have to observe the surrounding elements (N[i-2] and N[i+1]). negative one is equal to Nums N which is equal to negative infinity. So I'm hoping that so far, you know, maybe you can just jump into this. This method is very powerful and you can customize it to fit your needs, so let's see how it works in detail. The array is sorted in non-decreasing order and the elements are all positive. : Next permutation question. So based off of the values of p one mid and P two, were, what do you think p one and P two tell me with respect to the direction of the peak? So we're given an integer array of num, turn the index of peak. Like what do you see as the relationship between p one p two and M element which in this case is actually a peak. The confidence in that. Longest Palindromic Substring 6. So you have so many threads or processes or whatever, you have it doing one of those computations. One second. Thank you. So maybe give me a quick overview of what you're targeting with the interviews or what levels you're targeting to interview for, and what exactly you'd like to get out of this. 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Non Decreasing Array Leetcode Python So the problem allows us to use 1 move to change a number and then report whether the array can be made into a non-decreasing. Like, you know, the the leetcode-y software engineering interview type thing, just trying to get some get some rust out, you know. And this should be a nice easy O(N) time and O(1) space algorithm. : I know a man. do you where do you think the next peak will be in this case? https://neetcode.io/ - A better way to prepare for Coding Interviews Discord: https://discord.gg/ddjKRXPqtk Twitter: https://twitter.com/neetcode1 S. 2023 Interviewing.io Inc. Made with <3 in San Francisco. So this is actually really good. And you know, the precedents of even jumping into bin search itself was actually wrong, like this is something you should have caught immediate, like yeah, there is a possibility of two unsorted aspects in this a bin search won't apply. You know, the downside to it is even if it's not necessarily, it's not necessarily a high performance interview, oftentimes, they would consider this basic knowledge at L5 and above. So that's kind of the approach, I'll probably start coding here. So we're given an array of numbers and just check if it could become non decreasing. You can assume in most interviewers, interviews, you're not gonna be told what the ideal runtime is. But at the same time, there are some things that you said that were a bit wrong. Making statements based on opinion; back them up with references or personal experience. Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide, The future of collective knowledge sharing. : It's good to hear Awesome. Well, let's maybe start from here. Any questions on this I don't know if there's something I can expand on? So we can put this false statement and yeah, so that seems like it works. So paste it right here. There are only minor differences in the code of all four languages. So assuming we have a very huge array? Let's see the case is 321. We define an array is non-decreasing if nums [i] <= nums [i + 1] holds for every i ( 0-based) such that ( 0 <= i <= n - 2 ). And I'll just give you a quick debrief, and then we can go through the individual. Not the answer you're looking for? : Let me ask you this. Current elements is four. And so you catching the split point being an issue is really, really good. And if you encounter another one of those cases, then you return false. Alright, so let's see here. : Yeah I'm just going to create this, this little stub here, while, since I know what the title of the problem is. And I keep getting a bunch of Amazon people reaching out to me, so I was kind of looking towards like an L5 level thing. I'd say there's only one there. I think that's the main edge case there if you're gonna split into sub arrays, and send those sub arrays out to different processes. So I actually have a couple of questions I can suggest you look at after this. So this is what we were looking at. The problem becomes more difficult, however, once we realize that we're allowed to modify one element, which will naturally impact its relationship with the surrounding elements. If we iterate through the nums array (N), count the number of instances in which an element is lower than the one preceeding (err), and then see that count go above 1, then we should be able to return false. So you can say something like P one right here or something. And the gist of it is given an array of integers, purely integers, you're essentially allowed to change just one element to make sure that it's non decreasing, like non decreasing I.E. But how can you like leverage a computer like a modern day computer in order to process this as fast as possible? You know that's, that's just always a good idea. If seanpgallivan is not suspended, they can still re-publish their posts from their dashboard. How excited would you be to work with them? Non-decreasing Array Medium 5.4K 759 Companies Given an array nums with n integers, your task is to check if it could become non-decreasing by modifying at most one element. I think I mean, we would be moving farther, farther left, right. If you were to keep looking for the peak, where will we go? : Yeah, I guess. May 04, 2021. Appreciate your time. So just a quick feedback on that, but do see any way we can make this a bit more efficient, especially complexity wise, do you see as if there any unnecessary operations that you can avoid? And wherever my middle point is, it's telling me it's telling me what do you call it? Technically it's o n. So that wouldn't actually improve efficiency at all, if you did this kind of thing. 65. Because generally, you want to work with sorted array, right? Does that make sense? I have never almost never on the interviewer side. : I hear that. FYI, congrats on actually identifying the weakness even without me asking, that's actually a huge bluff. Frankly, I much rather get an inefficient solution that is well communicated. And then this peak ahead element is I guess this will also we can initialise at least to that Max negative is max size because we don't know nums really has anything right. I have this question here peak, find peak element. Really. Yeah. And I'm just gonna set that for the moment and a peak. : Oh, sorry. And so let's see, overall, your communication is great, so I really don't have any issues with that. Summary: You have a method that returns true is the array, passed as input, can become increasing . : General sense when you're looking for something? Alright, so let's see. Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place such that each unique element appears. Example 1: And that's one of those things, it's kind of hard to pan out. But even if we were to start here, let's say this was our P one. 2), Solution: Remove Palindromic Subsequences, Solution: Check If a String Contains All Binary Codes of Size K, Solution: Swapping Nodes in a Linked List, Solution: Best Time to Buy and Sell Stock with Transaction Fee, Solution: Generate Random Point in a Circle, Solution: Reconstruct Original Digits from English, Solution: Flip Binary Tree To Match Preorder Traversal, Solution: Minimum Operations to Make Array Equal, Solution: Determine if String Halves Are Alike, Solution: Letter Combinations of a Phone Number, Solution: Longest Increasing Path in a Matrix, Solution: Remove All Adjacent Duplicates in String II, Solution: Number of Submatrices That Sum to Target, Solution: Remove Nth Node From End of List, Solution: Critical Connections in a Network, Solution: Furthest Building You Can Reach, Solution: Find First and Last Position of Element in Sorted Array, Solution: Convert Sorted List to Binary Search Tree, Solution: Delete Operation for Two Strings, Solution: Construct Target Array With Multiple Sums, Solution: Maximum Points You Can Obtain from Cards, Solution: Flatten Binary Tree to Linked List, Solution: Minimum Moves to Equal Array Elements II, Solution: Binary Tree Level Order Traversal, Solution: Evaluate Reverse Polish Notation, Solution: Partitioning Into Minimum Number Of Deci-Binary Numbers, Solution: Maximum Product of Word Lengths, Solution: Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts, Solution: Construct Binary Tree from Preorder and Inorder Traversal, Solution: Minimum Number of Refueling Stops, Solution: Number of Subarrays with Bounded Maximum.
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